2z^2+5z=1

Solution for 2z^2+5z=1 equation:

2z^2+5z=1

We move all terms to the left:

2z^2+5z-(1)=0

a = 2; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·2·(-1)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{33}}{2*2}=\frac{-5-\sqrt{33}}{4}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{33}}{2*2}=\frac{-5+\sqrt{33}}{4}
$